test of revision 1 G9

Descrição

revision: fractions, radical, scientific notation
Zeinab Zeineddine
Quiz por Zeinab Zeineddine, atualizado more than 1 year ago
Zeinab Zeineddine
Criado por Zeinab Zeineddine aproximadamente 9 anos atrás
150
0

Resumo de Recurso

Questão 1

Questão
The GCD of 360 and 48 is
Responda
  • 24
  • 18
  • 28

Questão 2

Questão
(3×10³×3.6×(10²)^3)/(2.7×10⁻⁴)=
Responda
  • 4×10¹⁰
  • 4×10¹³
  • 4×10¹⁶

Questão 3

Questão
If x=(a+b)² and y=(a-b)² then x-y=
Responda
  • 2ab
  • 3ab
  • 4ab

Questão 4

Questão
If A=4√5-4 and B=5√5 then
Responda
  • A=B
  • A<B
  • A>B

Questão 5

Questão
Given the numbers: A=8/3+5÷(1-2/5) ; B=(55×10³×2¹⁰)/(10⁴×2⁹) ; C=(4+√5)(4-√5) ; D=2√45+√81-3√20+2 then A=B=C=D
Responda
  • True
  • False

Questão 6

Questão
Given: X=3√27+√48+√75 and Y=√12-2√48+√192. 1) Write X and Y in the form of a√b. 2) Compare X and Y. 3) Rationalize the denominator of: X/(Y+1) 4) Assume that the dimensions of the rectangle ABCD are U and V where U=√XY and V=X+Y. Calculate U and V, then evaluate the area of ABCD.
Responda
  • 1) X=18√3 ; Y=2√3 2) X>Y 3) X/(Y+1)=(18√3(2√3-1))/11 4) U=√XY=6√3 ; V=20√3 Area=XY=360.
  • 1) Y=18√3 ; X=2√3 2) X>Y 3) X/(Y+1)=(18√3(2√3-1))/11 4) U=√XY=3√3 ; V=2√3 Area=XY=12.

Questão 7

Questão
1) Rationalize the expression: √3/(3√2+√3) 2) Deduce that: √3/(3√2+√3)-(√6-11)/5 is an integer.
Responda
  • ) √3/(3√2+√3)=(√6+1)/5 2) √3/(3√2+√3)-(√6-11)/5=12/5
  • 1) √3/(3√2+√3)=(√6-1)/5 2) √3/(3√2+√3)-(√6-11)/5=2

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