Polynomdivision ( Niveau: Schwer )

Description

Aufnahmeprüfung Studienkolleg Mathematik Quiz on Polynomdivision ( Niveau: Schwer ) , created by IWKZ Tutorium on 11/06/2021.
IWKZ Tutorium
Quiz by IWKZ Tutorium, updated more than 1 year ago
IWKZ Tutorium
Created by IWKZ Tutorium almost 4 years ago
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Resource summary

Question 1

Question
Lösen Sie diese Polynomdivision! \[\frac{x^5 + 3x^4 - 5x^3 - 15x^2 + 4x + 12}{x^3 + 4x^2 + x - 6}\]
Answer
  • \[x^2 - x + 2\]
  • \[2x^2 + 3x - 2\]
  • \[x^2 - x - 2\]
  • \[x^2 - 2x - 1\]
  • Ich gebe auf!

Question 2

Question
Lösen Sie diese Polynomdivision! \[\frac{x^4 - 43x^2 + 18x + 360}{(x + 1)^2 - 25}\]
Answer
  • \[x^2 - 2x - 15\]
  • \[x^2 - 2x - 15 + \frac{1}{x^2 + 2x - 24}\]
  • \[3x^2 - x - 4\]
  • \[x^2 - 6x - 12\]
  • Ich gebe auf!

Question 3

Question
Lösen Sie diese Polynomdivision! \[\frac{6x^4 + 5x^3 + 4x - 4}{2x^2 + x - 1}\]
Answer
  • \[3x^2 - x + 2 + \frac{4x - 3}{2x^2 + x - 2}\]
  • \[3x^2 + x + 1 + \frac{4x - 3}{2x^2 + x - 1}\]
  • \[3x^2 + x + 1\]
  • \[3x^2 - x + 2\]
  • Ich gebe auf!

Question 4

Question
Lösen Sie diese Polynomdivision! \[\frac{2x^3 - 3x + 1}{2x - 1}\]
Answer
  • \[x^2 + \frac{1}{2}x - \frac{5}{4} - \frac{1}{4\cdot(2x - 1)}\]
  • \[x^2 + x - \frac{5}{2} - \frac{1}{2\cdot(2x - 1)}\]
  • \[x^2 - x + 27 - \frac{1}{2x - 1}\]
  • \[x^2 + \frac{\frac{5}{2}x + 1}{2x - 1}\]
  • Ich gebe auf!
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