Polynomdivision ( Niveau: Schwer )

Description

Aufnahmeprüfung Studienkolleg Mathematik Quiz on Polynomdivision ( Niveau: Schwer ) , created by IWKZ Tutorium on 11/06/2021.
IWKZ Tutorium
Quiz by IWKZ Tutorium, updated more than 1 year ago
IWKZ Tutorium
Created by IWKZ Tutorium about 3 years ago
1
0

Resource summary

Question 1

Question
Lösen Sie diese Polynomdivision! \[\frac{x^5 + 3x^4 - 5x^3 - 15x^2 + 4x + 12}{x^3 + 4x^2 + x - 6}\]
Answer
  • \[x^2 - x + 2\]
  • \[2x^2 + 3x - 2\]
  • \[x^2 - x - 2\]
  • \[x^2 - 2x - 1\]
  • Ich gebe auf!

Question 2

Question
Lösen Sie diese Polynomdivision! \[\frac{x^4 - 43x^2 + 18x + 360}{(x + 1)^2 - 25}\]
Answer
  • \[x^2 - 2x - 15\]
  • \[x^2 - 2x - 15 + \frac{1}{x^2 + 2x - 24}\]
  • \[3x^2 - x - 4\]
  • \[x^2 - 6x - 12\]
  • Ich gebe auf!

Question 3

Question
Lösen Sie diese Polynomdivision! \[\frac{6x^4 + 5x^3 + 4x - 4}{2x^2 + x - 1}\]
Answer
  • \[3x^2 - x + 2 + \frac{4x - 3}{2x^2 + x - 2}\]
  • \[3x^2 + x + 1 + \frac{4x - 3}{2x^2 + x - 1}\]
  • \[3x^2 + x + 1\]
  • \[3x^2 - x + 2\]
  • Ich gebe auf!

Question 4

Question
Lösen Sie diese Polynomdivision! \[\frac{2x^3 - 3x + 1}{2x - 1}\]
Answer
  • \[x^2 + \frac{1}{2}x - \frac{5}{4} - \frac{1}{4\cdot(2x - 1)}\]
  • \[x^2 + x - \frac{5}{2} - \frac{1}{2\cdot(2x - 1)}\]
  • \[x^2 - x + 27 - \frac{1}{2x - 1}\]
  • \[x^2 + \frac{\frac{5}{2}x + 1}{2x - 1}\]
  • Ich gebe auf!
Show full summary Hide full summary

Similar

Analytische Geometrie
Laura Overhoff
Untersuchung von ganzrationalen Funktionen
Laura Overhoff
Mathe Themen
Junsoo Kim
Cognitive Psychology Key Terms
Veleka Georgieva
Of Mice and Men
becky_e
EEO Terms
Sandra Reed
Unit 2 flashcards
C R
Organic Chemistry
Megan Tarbuck
Biology Unit 1a - GCSE - AQA
RosettaStoneDecoded
Test your English grammar skills
Brad Hegarty
SFDC App Builder 1 (26-50)
Connie Woolard