Question 1
Question
Which are true about bisubstrate reactions?
Answer
-
They use one substrate to yield two products
-
They use two substrates to yield two products
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The two types of bisubstrate reactions are transferase and redox reactions
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The two types of reactions are transferase and substitution reactions
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10% of reactions are bisubstrate
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60% of reactions are bisubstrate
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80% of reactions are bisubstrate
Question 2
Question
A transferase reaction is one where the functional group on one substrate is transferred to another substrate
Question 3
Question
In redox reactions, oxidising equivalents are transferred between substrates
Question 4
Question
In bisubstrate reactions with a sequential mechanism, all substrates must combine with the enzyme before the reaction can occur and products are released. Which of the following are also true of sequential bisubstrate reactions?
Answer
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Ordered sequential means that the substrates must bind in a particular order
-
Ordered sequential means that the substrates must bind and be released in a particular order
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Random sequential means that the products may be released in any order
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Random sequential means the substrates and products may be released in any order
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A Bi Bi reaction is bisubstrate
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A Bi Bi reaction has 2 substrates and 2 products
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The Lineweaver-Burk plot will be like that of uncompetitive inhibition
-
The Lineweaver-Burk plot will be like that of competitive inhibition
Question 5
Question
In Ping-Pong reactions, one or more products are released before all substrates have combined with the enzyme. Which of the following are also true of Ping-Pong reactions?
Answer
-
They are also referred to as "double displacement" reactions
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They are also referred to as "transient displacement" reactions
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Functional groups are transferred to the substrate directly
-
Functional groups are sometimes transferred to the enzyme
-
Enzyme intermediates in Ping-Pong are stable and can be purified and characterised
-
Enzyme intermediates in Ping-Pong are transient and can't be purified or characterised
-
The Lineweaver-Burk plots are like those for competitive inhibition
-
The Lineweaver-Burk plots are like those for uncompetitive inhibition
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Binding of one substrate will encourage binding of a second substrate
-
Binding of one substrate will inhibit binding of another one
Question 6
Question
Pancreatic triacylglycerol lipase catalyses the hydrolysis of the esters of fatty acids into free esters and is involved in protein digestion.
Question 7
Question
Pancreatic triacylglycerol lipase is secreted by the pancreas and also found in saliva and the stomach
Question 8
Question
Free esters released from lipid digestion of fatty acids, are more soluble than fatty acids.
Question 9
Question
Pancreatic triacylglycerol lipase catalyses the hydrolysis of triacylglycerols at position 1 and 2 on the glycerol molecule, and formation of 1,2-diacylglycerols and 2-acylglycerols
Question 10
Question
Which are true about lipase?
Answer
-
It is only present in an aqueous form
-
It is present in aqueous solution and as a micelle
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It requires an Mg co-factor for activity
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It requires a procolipase co-factor for activity
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Lipase is a zymogen
-
Procolipase is a zymogen
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The active site is permanently open
-
There is a flap that masks and closes the active site
Question 11
Question
What residues compose the catalytic triad of pancreatic triacylglycerol lipase?
Answer
-
His
-
Asp
-
Glu
-
Pro
-
Ser
-
Thr
-
Phe
-
Leu
Question 12
Question
The mechanism of triacylglycerol lipase:
Asp [blank_start]H-bonds to His, to increase its basicity[blank_end]. His can then [blank_start]abstract a proton from Ser[blank_end] to increase its nucleophilicity. Then Ser is able to launch a nucleophilic attack on the [blank_start]ester carbonyl of the fatty acids[blank_end] (the glycerol backbone). This forms a [blank_start]tetrahedral intermediate[blank_end], which is stabilised by [blank_start]an oxyanion hole[blank_end] (with residues [blank_start]Phe and Leu[blank_end]). The negative charge collapses as [blank_start]His protonates the glycerol backbone[blank_end] and the carbonyl reforms, releasing the first product, [blank_start]1,2-diacylglycerol[blank_end].
His then abstracts a proton from a molecule of water, forming a reactive [blank_start]hydroxyl anion[blank_end]. [blank_start]This OH[blank_end] can than attack the [blank_start]carbonyl carbon of the lipid[blank_end], forming another intermediate, which is stabilised in an oxyanion hole. The negative charge collapses when [blank_start]His protonates Ser[blank_end], reforming the catalytic Ser and allowing release of a 2nd product, [blank_start]a free fatty acid[blank_end].
Answer
-
H-bonds to His, to increase its basicity
-
launches attack on glycerol
-
coordinates an Mg ion
-
abstract a proton from Ser
-
abtract a proton from Asp
-
abstract a proton from water
-
ester carbonyl of the fatty acids
-
glycerol backbone
-
carboxylic acids
-
tetrahedral intermediate
-
planar intermediate
-
octahedral intermediate
-
an oxyanion hole
-
a Mg ion
-
the active site
-
Phe and Leu
-
Asp, Ser and His
-
Glu and Asp
-
His protonates the glycerol backbone
-
water donates a proton to the glycerol
-
1,2-diacylglycerol
-
2-acylglycerol
-
a free fatty acid
-
1-acylglycerol
-
hydroxyl anion
-
proton
-
hydroxyl radical
-
This OH
-
This H
-
This OH radical
-
carbonyl carbon of the lipid
-
free fatty acid chain
-
carboxylic acid
-
His protonates Ser
-
His protonates Asp
-
Ser abstracts a proton from water
-
Ser abstracts a proton from Asp
-
a 1-acylglycerol
-
free fatty acid or monoglyceride
-
free fatty acid
Question 13
Question
PLCA2 (phospholipase A2) requires a conformational change to function.
Question 14
Question
In PLCA2, the hydrophobic binding pocket is blocked by an inhibitor
Question 15
Question
The active site of PLCA2, consists of which of the following catalytic residues?
Question 16
Question
The active site contains a bound Mg.
Question 17
Question
PLCA2 mechanism: His is [blank_start]too far[blank_end] to activate for nucleophilic attack, so there is a [blank_start]second water[blank_end] which will later attack the scissile carbonyl carbon. Asp makes His more basic, His abstracts a proton from water. The activated water can nucleophilically attack the [blank_start]carbonyl carbon[blank_end], forming a tetrahedral intermediate. The role of Ca2+ is to coordinate the activated water molecule and eletrostatically stabilise negative charge on the oxygen of the tetrahedral intermediate ([blank_start]metal catalysis[blank_end]). Then there is the collapse of the tetrahedral intermediate. The [blank_start]His H-bonds[blank_end] to the hydroxyl group, causing it to abstract a proton from the lipid and reform water
Answer
-
too far
-
too weak
-
too basic
-
second water
-
Ser residue
-
carbonyl carbon
-
phosphate group
-
His residue
-
metal catalysis
-
electrostatic catalysis
-
acid-base catalysis
-
His H-bonds
-
Ser abstracts a proton
-
His donates a proton
Question 18
Question
Which are true of monotopic enzymes?
Answer
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They tend to bind hydrophobic substrates
-
Subtrates tend to be lipid-soluble and can diffuse through the lipid bilayer
-
Some oxidoreductases are monotopic and so are some peptidases
-
All transferases reactions are catalysed by monotopic enzymes
-
They bind hydrophilic, aqueous substrates
Question 19
Question
Which are true of multi-span enzymes?
Answer
-
Many peptidase are multispan and cleave peptides for transloaction
-
Transferases are a type of multispan enzyme
-
Multispan enzyme have multiple TMs
Question 20
Question
The gram negative cell wall is less robust and lacks mechanical strength as there is less peptidoglycan.
Question 21
Question
LpxC is an essential zinc-dependent deacetylase of bacterial lipid A synthesis producing UDP-3-O-N-glucosamine. Which of the following are true about it?
Answer
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It is only present in gram-negative bacteria
-
It catalyses the reaction from UDP-3-O-N-acetylglucosamine (UDP-GlcNac) --> UDP-3-O-N-glucosamine + acetate
-
It catalyses the reaction from UDP-3-O-N-acetylglucosamine (UDP-GlcNac) --> 3-O-N-acetylglucosamine + UDP
-
The key residues involved are Asp and His
-
The key residues involved are Glu and His
-
A bound Mg ion is required
-
A bound Zn ion is required
Question 22
Question
1 proposed mechanism for LpxC action:
[blank_start]Zn[blank_end] binds the active site. Glu acts as a base and [blank_start]deprotonates water[blank_end], making a good nucleophile to attack the [blank_start]carbonyl carbon[blank_end]. His stabilises the [blank_start]negative charge[blank_end] that develops. The negative charge collapses and [blank_start]Glu acts as acid[blank_end] and [blank_start]donates a proton back to[blank_end] the lipid. [blank_start]Acetic acid[blank_end] is also formed which loses a [blank_start]proton[blank_end] to form [blank_start]acetate[blank_end]. The product leaves and the Zn-lipid complex is displaced by water molecule and a new substrate.
Answer
-
Zn
-
Mg
-
deprotonates water
-
deprotonates Glu
-
protonates water
-
carbonyl carbon
-
hydroxyl group
-
alpha carbon
-
negative charge
-
positive charge
-
Glu acts as an acid
-
Glu acts as a base
-
donates a proton back to
-
abstracts a proton from
-
Acetic acid
-
UDP
-
proton
-
phosphate
-
acetate
-
UTP
Question 23
Question
Why is mechanism 1 for LpxC thought to be incorrect? What is the correct mechanism?
Answer
-
The mechanism suggests His is just stabilising, when it is actually acting as an acid by donating a proton to the tetrahedral intermediate as shown by mutagenesis
-
The correct mechanism is that the His is initially protonated, and then later protonates the lipid, and another water will bind Zn and be used
-
Mutating Glu to Ala, reduced activity, supporting the alternative mechanism
-
Mutating Glu to Ala, reduced activity, supporting both mechanisms
-
Mutating His to Ala, reduced activity, supporting both mechanisms
-
Mutating His to Ala, reduced activity, supporting the alternative mechanism
-
The mechanism suggests Asp is just stabilising, when mutagenesis shows that it is involved in the reaction as its mutation gives reduced activity
Question 24
Question
In terms of bacterial cell wall biosynthesis, which are true of transglycosylation?
Answer
-
The cell wall is purely an immune system physical barrier
-
The cell wall is an essential structure in scaffolding the cytoplasmic membrane and maintaining structural integrity of the bacteria
-
Glycosyltransferase (GT) and transpeptidase (TP) enzymes are involved in cell wall biosynthesis
-
There are antibiotics that inhibit the activity of GTs, such as beta-lactams (e.g. penicillin), glycopeptides (e.g., vancomycin) and glycolipopeptides
-
There are antibiotics that inhibit the activity of TPs, such as beta-lactams (e.g. penicillin), glycopeptides (e.g., vancomycin) and glycolipopeptides
-
Bacteria gain resistance to these antibiotics by accumulating mutations in the TP enzymes
-
Bacteria gain resistance to these antibiotics by mutating their cell wall
-
GT enzymes catalyse transfer of a sugar glycosyl nucleotide donor substrate to a specific hydroxyl group of another sugar, or to other acceptors (e.g. lipids)
-
GT enzymes transfer a glycosyl substrate to a tertiary hydroxyl on nucleotide sugar acceptors (e.g. lipids)
-
Peptidoglycan transglycosylation by the enzyme GT takes place through polymerization of lipid II substrates
Question 25
Question
To form peptidoglycans, enzymes exist to make trans additions of sugars. Which are true?
Answer
-
Glycosyltransferase catalyses the transfer of a sugar glycosyl to a nucleotide
-
Glycosyltransferase catalyses the linking of sugar molecules to other sugars or lipids
-
Transpeptidase links L-ala residues to other L-ala residues, cross linking them
-
Transpeptidase links D-ala residues to other D-ala residues, cross linking them
-
Transpeptidase is linked to glycosyltransferase by a linker and glycosyltransferase is partially embedded in the membrane
-
Lipids for cell wall composition are fed through the plasma membrane and deposited in the periplasmic space
-
Lipids for cell wall composition are derived from the cytoplasm and transported to the periplasm by active transport
Question 26
Question
Transglycosylation mechanism of glycosyltransferases (GTs):
Lipid binds to the membrane protein in a pocket and another lipid is fed through the membrane.
The E114 residue acts as a [blank_start]bronsted base[blank_end], abstracting a proton from the [blank_start]4-OH[blank_end] group of the [blank_start]lipid II acceptor[blank_end].
Oxygen activates to act as a good nucleophile and can make attack on [blank_start]C1 position[blank_end] of sugar moiety.
Glu E171 stabilises the negative charge forming (phosphate groups), coordinating [blank_start]pyrophosphate groups[blank_end] that form on the donor.
Stabilisation is either directly or indirectly, mediated by a [blank_start]divalent metal cation (e.g. Mg)[blank_end] to stabilise negative charge.
Upon attack on sugar, [blank_start]lipid-pyrophosphate[blank_end] leaving group can diffuse out of active site to give higher oligomeric state of lipid (through addition of more sugar to the incoming lipid).
Must go from [blank_start]boat to chair[blank_end] conformation (because SN2 attack)
Question 27
Question
Mechanism for lipid II polymerisation by TG (transglycosylase):
Glu acts as bronsted base and [blank_start]deprotonates 4-OH[blank_end] on [blank_start]GlcNAc[blank_end] of a lipid II molecule at the [blank_start]S1 site[blank_end].
This is followed by a simultaneous reaction with the C1 of another lipid II at S2 site with Glu.
[blank_start]Lys and Arg[blank_end] stabilise the negative charge of phosphate and facilitate its diffusion as a leaving group.
Then there is the [blank_start]transfer of the sugar and phosphate[blank_end] to growing chain.
Essentially, the lipid II’s glycosyl [blank_start]donor site (S2)[blank_end] reacts with the acceptor site (S1) of lipid II to form a [blank_start]β1–4-[blank_end] linked glycan chain.
Lipid keeps growing until certain length before leaving.