Chem test 2 quiz

What is the count rate of a sample of iodine-131 after 32 days if the initial count rate is 2016 counts per minute? The half life of iodine is 8 days. Use the table below to work out your answer Number of Hal Lives - Time (In days) - Count 0 - 0 - 2016 1 - [blank_start]8[blank_end] - [blank_start]1008[blank_end] 2 - [blank_start]16[blank_end] - [blank_start]504[blank_end] 3 - [blank_start]24[blank_end] - [blank_start]252[blank_end] 4 - [blank_start]32[blank_end] - [blank_start]126[blank_end]

What is the count rate of a sample of bismuth after 5 half lives if 1 half life takes 46 minutes and the initial count rate is 112 counts per minute? Number of half lives - Time (in minutes) - Count 0 - [blank_start]0[blank_end] - [blank_start]112[blank_end] 1 - [blank_start]46[blank_end] - [blank_start]56[blank_end] 2 - [blank_start]92[blank_end] - [blank_start]28[blank_end] 3 - [blank_start]138[blank_end] - [blank_start]14[blank_end] 4 - [blank_start]184[blank_end] - [blank_start]7[blank_end] 5 - [blank_start]220[blank_end] - [blank_start]3.5[blank_end]

What is the count rate of a sample of technetium after 5 half lives if 1 half life takes 6 hours and the initial count rate is 2016 counts per minute? Number of half lives - Time (in minutes) - Count 0 - [blank_start]0[blank_end] - [blank_start]2016[blank_end] 1 - [blank_start]6[blank_end] - [blank_start]1008[blank_end] 2 - [blank_start]12[blank_end] - [blank_start]504[blank_end] 3 - [blank_start]18[blank_end] - [blank_start]252[blank_end] 4 - [blank_start]24[blank_end] - [blank_start]126[blank_end] 5 - [blank_start]30[blank_end] - [blank_start]63[blank_end]

What is the count rate of a sample of strontium after 5 half lives if 1 half life takes 50 days and the initial count rate is 192 counts per minute? Number of half lives - Time (in minutes) - Count 0 - [blank_start]0[blank_end] - [blank_start]192[blank_end] 1 - [blank_start]50[blank_end] - [blank_start]96[blank_end] 2 - [blank_start]100[blank_end] - [blank_start]48[blank_end] 3 - [blank_start]150[blank_end] - [blank_start]24[blank_end] 4 - [blank_start]200[blank_end] - [blank_start]12[blank_end] 5 - [blank_start]250[blank_end] - [blank_start]6[blank_end]

What symbol of state would be used for each of the following: a) calcium carbonate (marble chip) = [blank_start]solid[blank_end] b) magnesium ribbon = [blank_start]solid[blank_end] c) iron fillings = [blank_start]solid[blank_end] d) oil = [blank_start]liquid[blank_end] e) sulfur powder = [blank_start]solid, aqueous[blank_end] f) salt water = [blank_start]liquid[blank_end] g) dissolved alcohol = [blank_start]liquid[blank_end] h) bubbles of carbon dioxide = [blank_start]gas[blank_end]

If Nitrogen = 16, how many electrons are there? [blank_start]7[blank_end]

If Nitrogen = 16, how many neutrons are there? [blank_start]9[blank_end]

If Nitrogen = 16, how many protons are there? [blank_start]9[blank_end]

If Aluminum = 30, how many electrons are there? [blank_start]13[blank_end]

If Aluminum = 30, how many neutrons are there? [blank_start]27[blank_end]

If Aluminum = 30, how many protons are there? [blank_start]27[blank_end]

If Sodium = 40, how many electrons are there? [blank_start]11[blank_end]

If Sodium = 40, how many neutrons are there? [blank_start]29[blank_end]

If Sodium = 40, how many protons are there? [blank_start]29[blank_end]

Balance the following equations: [blank_start]2[blank_end]Ca + O2
= [blank_start]2[blank_end]CaO N2 + [blank_start]3[blank_end] H2
= [blank_start]2[blank_end] NH3 [blank_start]2[blank_end] Cu2O + C
= [blank_start]4[blank_end] Cu + CO [blank_start]2[blank_end] H2O2
= [blank_start]2[blank_end] H2O + O2

Balance the following equations: [blank_start]2[blank_end] Na + MgF2 =
[blank_start]2[blank_end] NaF + Mg Mg + [blank_start]2[blank_end] HCl
= MgCl2 + H2 Cl2 + [blank_start]2[blank_end] KI
= [blank_start]2[blank_end] KCl + I2 [blank_start]2[blank_end] NaCl =
[blank_start]2[blank_end] Na + Cl2 [blank_start]4[blank_end] Na + O2
= [blank_start]2[blank_end] Na2O [blank_start]2[blank_end] Na + [blank_start]2[blank_end] HCl =
H2 + [blank_start]2[blank_end] NaCl [blank_start]2[blank_end] K + Cl2
= [blank_start]2[blank_end] KCl