Maths - Percentages

Description

Includes: Simple Interest, Increases and Decreases, Calculating the original Value & Repeated Percentage Changes
Martha Davies
Flashcards by Martha Davies, updated more than 1 year ago
Martha Davies
Created by Martha Davies over 8 years ago
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Resource summary

Question Answer
Maths Revision Cards Summer exams 2016
I borrow £3000 for 4 months at an interest rate of 2½% per month, How much interest do I pay? 3000 × 0.025 = 75 75 × 4 = £300
The population of a town increases from 22,500 by 7% What is the new population? 7% = 0.07 Multiplier for an increase of 7% = 1.07 22,500 × 1.07 = £24,075
A car decreases (depreciates) in value from £18,000 by 15% What is it now worth? 15% = 0.15 Multiplier for a decrease of 15% = 0.85 18,000 × 0.85 = £15,300
A house was worth £135,000 last year but is now worth £150,000 Calculate the percentage increase Work out the actual increase 15,000 - 135,000 = 15,000 work out this increase as a percentage of the original value 15,000 -------- = 0.11111 . . . . . 135,000 = 11%
A coat price has decreased by 20% and is now £150 What was the original price? Original × Multiplier = New Original × 1.2 = £150 Original = 150 ------ = £125 1.2
The population of a village has decreased by 10% and is now 7668. What was the population before this decrease? Original × Multiplier = New Original × 0.9 = 7668 Original = 7668 ------- = 8520 0.9
The population of a village increased from 3540 by 10% then decreased by 4%. what is the resulting population? 3540 × 1.1 × 0.96 = 3738.24 New Population = 3738
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