Questão 1
Questão
The study of the rates of enzyme catalysed reactions is called..
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enzyme kinetics
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enzyme thermodynamics
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enzyme Vmax
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enzymatics
Questão 2
Questão
The simplest way to investigate reaction rate is to monitor [blank_start]increase[blank_end] in reaction product against time. This can be done at a variety of [blank_start]substrate[blank_end] concentrations and the initial velocity of the reaction determined. Eventually the reaction will reach a plateau when the reaction equilibrium has been attained.
In reality enzyme kinetics is more readily understood if we only consider the [blank_start]forward[blank_end] reaction and we define V0 as the number of [blank_start]moles[blank_end] of product formed per second when the reaction is just beginning at t ~0
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increase
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decrease
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substrate
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enzyme
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forward
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backwards
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moles
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grams
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litres
Questão 3
Questão
add labels to the enzyme kinetics equation
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enzyme
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substrate
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enzyme.substrate complex
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Product
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rate constants
Questão 4
Questão
What are the preconditions of the enzyme kinetics equation
Questão 5
Questão
when is this equation useful?
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when looking at enzyme kinetics
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when calculating Kd
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when substrate concentration is smallet than the enzyme concentration
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When calculating the colume of the substrate added
Questão 6
Questão
Label the Michaelis-Menten Relationship
Questão 7
Questão
The Michaelis constant is a measure of the affinity of the enzyme for its substrate
and is expressed as..
Questão 8
Questão 9
Questão
A low KM means a low affinity of enzyme for substrate
Questão 10
Questão
How can you find Kcat?
Questão 11
Questão
kcat is the number of substrate molecules transformed per molecule of enzyme per second (units are s-1) or i.e...
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turnover number
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equilibrium number
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catalytic number
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transformation number
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critical number
Questão 12
Questão
Label each column
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Enzymes
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Km (mol.L-1)
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kcat (s-1)
Questão 13
Questão
Enzymes are capable of working on a number of substrates, some better than others. The efficiency of these enzymes depends both on kcat and on KM.
Questão 14
Questão
The specificity constant is defined as..
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kcat/KM
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kcat
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KM
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Vmax
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Vo
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Kd/kcat
Questão 15
Questão
The [blank_start]higher[blank_end] the kcat and [blank_start]the lower[blank_end] the KM the bigger the specificity constant.
The best substrate for an enzyme will have the [blank_start]highest[blank_end] specificity constant.
This constant also describe the [blank_start]catalytic[blank_end] efficiency of enzymes.
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higher
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lower
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the lower
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the higher
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highest
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lowest
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catalytic
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catabolic
Questão 16
Questão
What is the name of this equation?
Questão 17
Questão
Label the Lineweaver plot
Questão 18
Questão
Inhibitors can also be very useful substances used as pharmaceuticals. Examples would be [blank_start]penicillin[blank_end] which inhibits the enzyme responsible for cell wall biosynthesis in certain bacteria [blank_start]and aspirin (methyl salicylate)[blank_end] which binds to and inhibits cyclooxygenase enzymes.
Questão 19
Questão
There are two types of inhibition, REVERSIBLE and IRREVERSIBLE.
Reversible inhibition is said to be [blank_start]COMPETITIVE[blank_end] whereas irreversible inhibition [blank_start]can be NON-COMPETITIVE or UNCOMPETITIVE.[blank_end]
Questão 20
Questão
This inhibition is...
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Reversible Competitive
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Reversible Non-competitive
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Irreversible Uncompetitive
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Irreversible Non-competitive
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Irreversible Competitive
Questão 21
Questão
In competitive inhibition KM is [blank_start]increased[blank_end] but Vmax remains unaltered.
An example of competitive inhibition is inhibition of succinate dehydrogenase by malonate. Malonate competes with succinate for [blank_start]binding[blank_end] at the active site but cannot be converted to fumerate. [blank_start]Increasing[blank_end] the concentration of succinate competes out the inhibitor.
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increased
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decreased
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binding
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inhibition
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Increasing
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Decreasing
Questão 22
Questão
This inhibition is...
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Reversible competitive
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Irreversible competitive
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Irreversible uncompetitive
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Reversible uncompetitive
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Reversible non-competitive
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Irreversible non-competitive
Questão 23
Questão
In uncompetitive inhibition KM is [blank_start]unaltered or appears reduced[blank_end] and Vmax is [blank_start]dramatically reduced[blank_end]
There is no requirement for the inhibitor to resemble the structure of the [blank_start]substrate[blank_end]. The inhibitor does not bind to free enzyme only to [blank_start]ES complexed[blank_end] enzyme. It is believed that these type of inhibitors distort the active site region [blank_start]preventing[blank_end] further substrate turnover.
Questão 24
Questão
This inhibition is..
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Reversible Non-competitive
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Reversible competitive
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Irreversible Non-competitve
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Irreversible competitive
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Reversible uncompetitive
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Irreversible uncompetitive
Questão 25
Questão
A non-competitive inhibitor binds to both the free E and the ES complex and the effect of this is to [blank_start]lower[blank_end] the effective number of enzyme molecules. The rsult is [blank_start]a decrease[blank_end] in Vmax as a result of changes in [blank_start]kcat[blank_end].
Vmax is [blank_start]reduced[blank_end] and KM is not normally effected
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lower
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increase
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a decrease
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an increase
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kcat
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Km
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Vo
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Kd
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reduced
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increased
Questão 26
Questão
What are the EXAMPLES OF IRREVERSIBLE ENZYME INHIBITORS
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Aspirin
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Cyanide
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Penicillin
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Retinol
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Haemoglobin
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Paracetamol