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6356499
Allgemeine und molekulare Genetik 2
Descrição
Bachelor Mikrobiologie Quiz sobre Allgemeine und molekulare Genetik 2, criado por Anna Ullrich em 15-09-2016.
Sem etiquetas
mikrobiologie
bachelor
Quiz por
Anna Ullrich
, atualizado more than 1 year ago
Mais
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Criado por
Anna Ullrich
aproximadamente 8 anos atrás
17
1
0
Resumo de Recurso
Questão 1
Questão
What's right: Synthetic lethality ...
Responda
Combinatorial effects between alleles or substances
Effects in synthetic biology
An effect specific to a double mutation (not seen in the singles)
An effect specific to a mutation in combination with a SMI-small molecule inhibitor (not seen by either mutation or SMI alone)
Questão 2
Questão
What's right: Phage lambda lysogen ...
Responda
C1 represses lambda's lysogenic genes, c2 activates int- and c1 transcription, c3 stabilizes c2
C1 represses lambda's lysogenic genes, c2 represses int- and c1 transcription, c3 destabilizes c2
C1 represses lambda's lytic genes, c2 activates int- and c1 transcription, c3 stabilizes c2
C1 represses lambda's lytic genes, c2 represses int- and c1 transcription, c3 destabilizes c2
Questão 3
Questão
What's right: Bacterial transformation
Responda
The mechanism of gram+ and gram- DNA uptake is not related
Gram- bacteria possess an outer membrane requiring an additional pore for DNA uptake
Gram+ bacteria possess an outer membrane requiring an additional pore for DNA uptake
Gram+ and gram- bacteria have a pilus structure, a dsDNA receptor and an inner membrane pore in common
Questão 4
Questão
What's right: Intra- vs extragenic complementation
Responda
Genetic complementation between mutations in different genes does not require wild type alleles
Extragenic complementation is rare and requires mutations in different functional domains
Intragenic complementation is rare and depends on the presence of domains that function independently
Molecular complementation depends on addition of the wild gene
Questão 5
Questão
What's right: Dominant vs epistatic
Responda
a is epistatic to locus b , if the double mutant (a,a/b,b) has the same phenotype as the single mutant (a,a)
a is epistatic to b, means: Pht(a,b)=Pht(a,B) .. (although Pht(A,b)≠Pht(A,B))
dominant : Pht(A,A)=Pht(a,A)
dominant relates alleles of 1 gene, epistatic relates an allele to another gene
A is dominant over a: Pht(a,A) = Pht(a,a)
Questão 6
Questão
What's right: gene vs allele
Responda
a ncRNA is not encoded by a gene, because it is not translated
a centromere is not a gene, because it is not transcribed
a bacterial cistron is not a gene, because it contains several functional units
a gene is a functional unit in the genome, activated by transcription while an allele is a sequence variant of a gene
a bacterial operon is not a gene, because it contains several functional units
Questão 7
Questão
What's right: Falsifyability
Responda
According to Popper’s critical rationalism (P.c.r), a Sc.Hyp can’t be claimed true, without evidence
According to P.c.r. a single experiment, if well performed, can prove a hypothesis forever
According to P.c.r. a single experiment, if well performed, can disprove a hypothesis forever
According to P.c.r. a scientific hypothesis must make a prediction, which can be proven wrong
Questão 8
Questão
What's right: Suppressor mutation
Responda
A suppressor mutation blocks the expression of another gene
A suppressor mutation can’t occur in the same gene
A suppressor mutation must occur in tRNA
A suppressor blocks the appearance of a mutant phenotype
Questão 9
Questão
What's right: What is the phenotype?
Responda
Many genes do not cause a phenotype
The phenotype of a given mutation must be detectable under all conditions
The phenotype of a mutation can change according to the situation
The phenotype ist the observable impact of an allele
Questão 10
Questão
Connect the topic with the correct boxes/key words ... BACTERIAL RECOMBINEERING
Responda
attB/P/L/R
targetted DSB
RE enzyme free assembly of bacterial, genome-size DNA
Efficient, RE enzyme free transfer of inserts between plasmids
Inhibition of RecBCD
RE enzyme free sub cloning from large inserts
RE enzyme free correction of genetic defects in vivo
Bacterial immune system
Exo, Beta, Gam
Edition through DSB-repair
Questão 11
Questão
Connect the topic with the correct boxes/key words ... GATEWAY TECHNOLOGY
Responda
attB/P/L/R
targetted DSB
RE enzyme free assembly of bacterial, genome-sized DNA
Efficient, RE enzyme free transfer of inserts between plasmids
RE enzyme free sub cloning from large inserts
RE enzyme free correction of genetic defects in vivo
Bacterial immune system
Exo, Beta, Gam
Editing through DSB-repair
Cloning from donor to recipient
Questão 12
Questão
Connect the topic with the correct boxes/key words ... CRISPR
Responda
attB/P/L/R
targetted DSB
RE enzyme free assembly of bacterial, genome-size DNA
Efficient, RE enzyme free transfer of inserts between plasmids
Inhibition of RecBCD
RE enzyme free subcloning from large inserts
RE enzyme free correction of genetic defects in vivo
Bacterial immune system
Exo, Beta, Gam
Editing through DSB-repair
Questão 13
Questão
Connect the topic with the correct boxes/key words ... YEAST RECOMBINEERING
Responda
attB/P/L/R
targetted DSB
RE enzyme free assembly of bacterial, genome-size DNA
Efficient, RE enzyme free transfer of inserts between plasmids
Inhibition of RecBCD
RE enzyme free subcloning from large inserts
RE enzyme free correction of genetic defects in vivo
Bacterial immune system
Exo, Beta, Gam
Editing through DSB-repair
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